document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1005135>Question 1005135</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If L is a line perpendicular to 2y-3x=1, then the sum of the slopes of the two lines is:\r<BR>\n" );
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document.write( "A) 5/6\r<BR>\n" );
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document.write( "B)3/2\r<BR>\n" );
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document.write( "c)2/3\r<BR>\n" );
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document.write( "D)-1\r<BR>\n" );
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document.write( "E)1/5<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #621448 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=621448\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The slope of 2y-3x=1 can be found by solving for y...<BR>\n" );
document.write( "2y = 3x + 1<BR>\n" );
document.write( "y = (3/2)x + 1/2<BR>\n" );
document.write( "Its slope is 3/2.<BR>\n" );
document.write( "Its perpendicular slope is -2/3.<BR>\n" );
document.write( "Adding the we get<BR>\n" );
document.write( "3/2 - 2/3 = 5/6<BR>\n" );
document.write( "Choice A. </SPAN>\n" );
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