document.write( "Question 85973: Find the length of each side of the rectangle so that it has the given perimeter.\r
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document.write( "width 2x-5\r
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document.write( "P= 50in \n" );
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Algebra.Com's Answer #62140 by tutorcecilia(2152)![]() ![]() You can put this solution on YOUR website! Use the formula for the perimeter of a rectangle: \n" ); document.write( "P=2(length+width) \n" ); document.write( "Plug-in the values and solve for the missing term (x) \n" ); document.write( "P=50 \n" ); document.write( "Width = 2x-5 \n" ); document.write( "Length=x \n" ); document.write( ". \n" ); document.write( "P=2(length+width) \n" ); document.write( "50=2[x+(2x-5)] \n" ); document.write( "50=2(x+2x-5) \n" ); document.write( "50=2(3x-5) \n" ); document.write( "50/2=2/2(3x-5) \n" ); document.write( "25=3x-5 \n" ); document.write( "25+5=3x \n" ); document.write( "30=3x \n" ); document.write( "30/3=3x/3 \n" ); document.write( "10=x (length) \n" ); document.write( ". \n" ); document.write( "Width = 2x-5=2(10)-5=20-5=15 \n" ); document.write( ". \n" ); document.write( "check by plugging all of the values back into the original formula: \n" ); document.write( "P=2(length+width) \n" ); document.write( "50=2(10+15) \n" ); document.write( "50=2(25) \n" ); document.write( "50=50 [checks out]\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |