document.write( "Question 85973: Find the length of each side of the rectangle so that it has the given perimeter.\r
\n" ); document.write( "\n" ); document.write( "width 2x-5\r
\n" ); document.write( "\n" ); document.write( "P= 50in
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Algebra.Com's Answer #62140 by tutorcecilia(2152)\"\" \"About 
You can put this solution on YOUR website!
Use the formula for the perimeter of a rectangle:
\n" ); document.write( "P=2(length+width)
\n" ); document.write( "Plug-in the values and solve for the missing term (x)
\n" ); document.write( "P=50
\n" ); document.write( "Width = 2x-5
\n" ); document.write( "Length=x
\n" ); document.write( ".
\n" ); document.write( "P=2(length+width)
\n" ); document.write( "50=2[x+(2x-5)]
\n" ); document.write( "50=2(x+2x-5)
\n" ); document.write( "50=2(3x-5)
\n" ); document.write( "50/2=2/2(3x-5)
\n" ); document.write( "25=3x-5
\n" ); document.write( "25+5=3x
\n" ); document.write( "30=3x
\n" ); document.write( "30/3=3x/3
\n" ); document.write( "10=x (length)
\n" ); document.write( ".
\n" ); document.write( "Width = 2x-5=2(10)-5=20-5=15
\n" ); document.write( ".
\n" ); document.write( "check by plugging all of the values back into the original formula:
\n" ); document.write( "P=2(length+width)
\n" ); document.write( "50=2(10+15)
\n" ); document.write( "50=2(25)
\n" ); document.write( "50=50 [checks out]\r
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