document.write( "Question 1005087: the perimeter of a rhombus is 120 ft. and one of its diagonal has a length of 40 ft. find the area of the rhombus? \n" ); document.write( "

Algebra.Com's Answer #621393 by AnlytcPhil(1806) $\"\"$ $\"About$

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document.write( "The rhombus looks like the figure below.  Since its perimeter \r\n" );
document.write( "is 120 ft., each equal length side is 120/4 = 30 ft.\r\n" );
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document.write( "We draw the other diagonal in red, which bisects the \r\n" );
document.write( "green 40 ft. diagonal into two 20 ft. line segments.\r\n" );
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document.write( "So the rhombus consists of 4 right triangles, so we\r\n" );
document.write( "find the area of one of them and multiply by 4. Here is\r\n" );
document.write( "just one of them:\r\n" );
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document.write( "We use the Pythagorean theorem to find its height,\r\n" );
document.write( "We know its base is b=20 and its hypotenuse is 30,\r\n" );
document.write( "we find a, the green height:\r\n" );
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document.write( "The area of the above right triangle is given by \r\n" );
document.write( "the formula:\r\n" );
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document.write( "So the area of the rhombus is 4 times that or\r\n" );
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document.write( "answer = , or about 894.427191 sq. ft.\r\n" );
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document.write( "Edwin

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