document.write( "Question 1005018: if you invest $5000 between two accounts paying 7% and 9% annual interest, respectively. If the total interest earned for the year was $430 how much was invested at each rest \n" ); document.write( "
Algebra.Com's Answer #621347 by addingup(3677)![]() ![]() You can put this solution on YOUR website! .07x+.09(5000-x)= 430 \n" ); document.write( ".07x+450-.09x= 430 \n" ); document.write( "-.02x= -20 \n" ); document.write( "x= 1000 was invested at 7% and \n" ); document.write( "5000-1000= 4000 was invested at 9% \n" ); document.write( "Proof \n" ); document.write( "1000*.07= 70 \n" ); document.write( "4000*.09= 360 \n" ); document.write( "_ _ _ _ _------ \n" ); document.write( "Total.....430 We have the correct answer. \n" ); document.write( "J \n" ); document.write( " \n" ); document.write( " |