document.write( "Question 1004991: Find the slope-intercept form of the equation that passes through the given point and is perpendicular to the given line.
\n" ); document.write( "(6,-1) and 3y+x=3 \n" ); document.write( "

Algebra.Com's Answer #621331 by stanbon(75887) $\"\"$ $\"About$

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Find the slope-intercept form of the equation that passes through the given point and is perpendicular to the given line.
\n" ); document.write( "(6,-1) and 3y+x=3
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\n" ); document.write( "Find the slope of the given line::
\n" ); document.write( "y = (-1/3)x + 1
\n" ); document.write( "slope = -1/3)
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\n" ); document.write( "Find the slope of the perpendicular line:
\n" ); document.write( "slope = 3
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\n" ); document.write( "Equation Form::
\n" ); document.write( "y = mx + b
\n" ); document.write( "Solve for \"b\" using the point and the slope values::
\n" ); document.write( "-1 = 3(6) + b
\n" ); document.write( "b = -19
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\n" ); document.write( "Equation:
\n" ); document.write( "y = 3x - 19
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H
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