document.write( "Question 86020: Factor the polynomial. if can not be factored write prime\r
\n" ); document.write( "\n" ); document.write( "x squared +22x + 121 \n" ); document.write( "

Algebra.Com's Answer #62132 by Earlsdon(6294) $\"\"$ $\"About$

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Factor:
\n" ); document.write( " $\"x%5E2%2B22x%2B121\"$ Notice that the constant term (121) is a perfect square $\"121+=+11%5E2\"$ which suggests the trinomial might, itself, be a perfect square.\r
\n" ); document.write( "\n" ); document.write( "Let's try:
\n" ); document.write( " $\"x%5E2%2B22x%2B121+=+%28x%2B11%29%28x%2B11%29\"$ You can check this using FOIL.
\n" ); document.write( " $\"%28x%2B11%29%28x%2B11%29+=+x%5E2%2B11x%2B11x%2B121\"$ Simplify.
\n" ); document.write( " $\"%28x%2B11%29%5E2+=+x%5E2%2B22x%2B121\"$
\n" ); document.write( "The factors are:
\n" ); document.write( " $\"%28x%2B11%29%5E2\"$ \n" ); document.write( "

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