document.write( "Question 1004968: Need equation:Jane leaves school and walks home at a rate of 4 mi/hr. 15 minutes later, Bill finds a book that Jane forgot and runs at a rate of 8 mi/hr. How many minutes will it take Bill to catch up with Jane?\r
\n" ); document.write( "\n" ); document.write( "I know she has walked 1 mile in 15 minutes (1/4 hour @ 4 mi/hr is 1 mile). At his pace, it will take 1/2 that time to walk the same distance. But do I consider that she is walking away from him at same time? Don't know how to put in equation format.
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Algebra.Com's Answer #621303 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Jane's head start in miles:
\n" ); document.write( "\"+4%2A%281%2F4%29+=+1+\" mi
\n" ); document.write( "------------------
\n" ); document.write( "Now imagoine that you start a stopwatch
\n" ); document.write( "when Bill leaves.
\n" ); document.write( "Let \"+t+\" = time in hours on stopwatch
\n" ); document.write( "when Bill catches Jane
\n" ); document.write( "Let \"+d+\" = distance in miles Bill travels
\n" ); document.write( "until he catches up with Jane
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\n" ); document.write( "Bills equation:
\n" ); document.write( "(1) \"+d+=+8t+\"
\n" ); document.write( "Jane's equation:
\n" ); document.write( "(2) \"+d+-+1+=+4t+\"
\n" ); document.write( "----------------
\n" ); document.write( "Substitute (1) into (2)
\n" ); document.write( "(2) \"+8t+-+1+=+4t+\"
\n" ); document.write( "(2) \"+4t+=+1+\"
\n" ); document.write( "(2) \"+t+=+1%2F4+\"
\n" ); document.write( "It will take Bill 15 min to catch Jane
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\n" ); document.write( "check:
\n" ); document.write( "(1) \"+d+=+8t+\"
\n" ); document.write( "(1) \"+d+=+8%2A%281%2F4%29+\"
\n" ); document.write( "(1) \"+d+=+2+\"
\n" ); document.write( "and
\n" ); document.write( "(2) \"+d+-+1+=+4t+\"
\n" ); document.write( "(2) \"+d+-+1+=+4%2A%28+1%2F4%29+\"
\n" ); document.write( "(2) \"+d+-+1+=+1+\"
\n" ); document.write( "(2) \"+d+=+2+\"
\n" ); document.write( "OK
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