document.write( "Question 1004968: Need equation:Jane leaves school and walks home at a rate of 4 mi/hr. 15 minutes later, Bill finds a book that Jane forgot and runs at a rate of 8 mi/hr. How many minutes will it take Bill to catch up with Jane?\r
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document.write( "I know she has walked 1 mile in 15 minutes (1/4 hour @ 4 mi/hr is 1 mile). At his pace, it will take 1/2 that time to walk the same distance. But do I consider that she is walking away from him at same time? Don't know how to put in equation format. \n" );
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Algebra.Com's Answer #621303 by josmiceli(19441)![]() ![]() You can put this solution on YOUR website! Jane's head start in miles: \n" ); document.write( " \n" ); document.write( "------------------ \n" ); document.write( "Now imagoine that you start a stopwatch \n" ); document.write( "when Bill leaves. \n" ); document.write( "Let \n" ); document.write( "when Bill catches Jane \n" ); document.write( "Let \n" ); document.write( "until he catches up with Jane \n" ); document.write( "----------------------------------- \n" ); document.write( "Bills equation: \n" ); document.write( "(1) \n" ); document.write( "Jane's equation: \n" ); document.write( "(2) \n" ); document.write( "---------------- \n" ); document.write( "Substitute (1) into (2) \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "It will take Bill 15 min to catch Jane \n" ); document.write( "----------------------------- \n" ); document.write( "check: \n" ); document.write( "(1) \n" ); document.write( "(1) \n" ); document.write( "(1) \n" ); document.write( "and \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "OK \n" ); document.write( " |