document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1004910>Question 1004910</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A Picture frame measures 12cm by 8cm and is surrounded by a frame whose area is 52cm squared. Find the width of the frame in cm correct to 3 significant figures. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #621276 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=621276\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call the extra part of the length and width, x.<BR>\n" );
document.write( "Thus the framed dimensions are 12+x and 8+x.<BR>\n" );
document.write( "Originally the frame's area is 12x8 = 96 cm^2<BR>\n" );
document.write( "With the frame added on, the new total area is 96 + 52 = 148 cm^2.<BR>\n" );
document.write( "So we have<BR>\n" );
document.write( "(12+x)(8+x)=148<BR>\n" );
document.write( "x^2 + 20x + 96 = 148<BR>\n" );
document.write( "x^2 + 20x - 52 = 0<BR>\n" );
document.write( "This won't factor, so we apply the quadratic formula...<BR>\n" );
document.write( "x = (-20 +- sqrt(20^2 + 208)) / 2<BR>\n" );
document.write( "x = (-20 +- sqrt(608)) / 2<BR>\n" );
document.write( "x = -10 +- sqrt(152)<BR>\n" );
document.write( "We must use the positive root and get<BR>\n" );
document.write( "x = -10 + 12.33 = 2.33<BR>\n" );
document.write( "So the dimensions of the framed picture are approximately 14.33 cm by 10.33 cm. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );