document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1004902>Question 1004902</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the slope-intercept form of the equation that passes through the given point and is perpendicular to the given line.\r<BR>\n" );
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document.write( "(-3,1) and y=-3x+7 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #621258 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=621258\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If the line you want is perp. to y = -3x + 7, then the slope you want is 1/3.<BR>\n" );
document.write( "Plug the info into y = mx + b and get<BR>\n" );
document.write( "1 = (1/3)(-3) + b<BR>\n" );
document.write( "1 = -1 + b<BR>\n" );
document.write( "b = 2<BR>\n" );
document.write( "and the line you want is<BR>\n" );
document.write( "y = (1/3)x + 2 </SPAN>\n" );
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