document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1004909>Question 1004909</A>: <I><SPAN STYLE=\"word-break: break-all;\"> log3(2x-3)-log3(x+2)=3\r<BR>\n" );
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document.write( "PLEASE HELP! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #621251 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=621251\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Using the laws of exponents<BR>\n" );
document.write( "log3(2x-3)-log3(x+2)=3<BR>\n" );
document.write( "becomes<BR>\n" );
document.write( "log(3) ((2x-3)/(x+2)) = 3<BR>\n" );
document.write( "Now exponentiate 3-to-the and get<BR>\n" );
document.write( "(2x-3)/(x+2) = 27<BR>\n" );
document.write( "Now multiply by x+2 and solve<BR>\n" );
document.write( "2x - 3 = 27x + 54<BR>\n" );
document.write( "-57 = 25x<BR>\n" );
document.write( "x = -57/25 </SPAN>\n" );
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