document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1004897>Question 1004897</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The spinners are spun and the results are added. Find P(sum is 8).<BR>\n" );
document.write( "Spinner #1.) 3/4 is 4. 1/4 is 2 <BR>\n" );
document.write( "Spinner #2.) 1/3 is 2. 1/3 is 4. 1/3 is 6. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #621240 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=621240\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> To get a sum of eight, we would need a 4 and a 4 or a 2 and a 6...we add the probabilities for each...<BR>\n" );
document.write( "For a 4 and a 4, we multiply 3/4 and 1/3 to get 1/4.<BR>\n" );
document.write( "For a 2 and a 6, we multiply 1/4 and 1/3 to get 1/12.<BR>\n" );
document.write( "Now add 1/4 + 1/12 = 4/12 = 1/3 </SPAN>\n" );
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