document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1004896>Question 1004896</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Put the equation in standard form with a positive x coefficient.\r<BR>\n" );
document.write( "\n" );
document.write( "Y-2=-2/5(X-8) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #621236 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=621236\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> From y - 2 = (-2/5)(x - 8), let's multiply everything by five to clear fractions...we get<BR>\n" );
document.write( "5y - 10 = -2(x - 8)<BR>\n" );
document.write( "5y - 10 = -2x + 16<BR>\n" );
document.write( "and putting it into standard form we get<BR>\n" );
document.write( "2x + 5y = 26 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );