document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1004892>Question 1004892</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do you rewrite the expression cos^2(2x) in terms of the first power of the cosine? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #621234 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=621234\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Well cos(2x) = cos^2(x) - sin^2(x) = 2cos^2(x) - 1<BR>\n" );
document.write( "and we will need to square that...so<BR>\n" );
document.write( "cos^2(2x) = [2cos^2(x) - 1]^2 = 4cos^4(x) - 4cos^2(x) + 1 </SPAN>\n" );
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