document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1004880>Question 1004880</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Sharon	plans	to	mix	peppermints	worth	$1.20	per	lb	with	chocolates	worth	<BR>\n" );
document.write( "$2.40	per	lb	to	get	a	40	lb	mix	that	is	worth	$1.65	per	lb.	How	much	of	each	<BR>\n" );
document.write( "should	she	use? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #621227 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=621227\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> p+c= 40lb subtract p from both sides: c= 40-p Used this in the next formula:<BR>\n" );
document.write( "1.20p+2.40c= 1.65(40) Now substitute for c:<BR>\n" );
document.write( "1.20p+2.40(40-p)= 1.65(40)<BR>\n" );
document.write( "1.20p+96-2.40p= 66<BR>\n" );
document.write( "-1.2p= -30<BR>\n" );
document.write( "p= -30/-1.2= 25lbs of peppermint and <BR>\n" );
document.write( "c= 40-25= 15 lbs of chocolate </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );