document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1004876>Question 1004876</A>: <I><SPAN STYLE=\"word-break: break-all;\"> to earn a B in a course, you must have a final average of 84%. On the first three examinations, you have grades of 80%, 72%, and 86%. if the final examination counts as two grades, what must you get on the final to get a B on the course? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #621220 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=621220\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> We'll call the final grade x. Since it equals two grades: 2x<BR>\n" );
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document.write( "(80+72+86+2x)/5= 84<BR>\n" );
document.write( "(238+2x)/5= 84 Multiply both sides times 5 (the magical rule of \"do no harm\" in equations, always do to one side what you do to the other):<BR>\n" );
document.write( "238+2x= 420 Subtract 238 from both sides:<BR>\n" );
document.write( "2x= 182<BR>\n" );
document.write( "x= 91  </SPAN>\n" );
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