document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1004864>Question 1004864</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A sandbox 3.5 ft on each side is placed on a 79 1/3rd <--(fraction)ft by 72ft lot. Find the area of the lawn?\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #621210 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=621210\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The area of the lawn which I will call x is L*W-S^2, where S^2 is the area of the square sand box. Using the numbers in the problem:<BR>\n" );
document.write( "x= (79 1/3*72)-(3.5^2). Let's solve the first parenthesis:<BR>\n" );
document.write( "79 1/3 Convert this mixed number to a fraction:<BR>\n" );
document.write( "(79*3)+1= 237+1= 238. So, our number is 238/3<BR>\n" );
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document.write( "238/3*72= 238/3*72/1= (238*72)/(3*1)= 5712 is the total area. Now let's deduct the sandbox:<BR>\n" );
document.write( "5712-3.5^2= 5712-12.25= 5699.75 is the area of the lawn  </SPAN>\n" );
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