document.write( "Question 1004834: Find the lengths of the sides of the triangle and area with the vertices A(-2,-3) B(6,1) & C (-2,-5) \n" ); document.write( "
Algebra.Com's Answer #621199 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "Find the lengths of the sides of the triangle and area with the vertices:\r
\n" ); document.write( "\n" ); document.write( " A(\"-2\",\"-3\") B(\"6\",\"1\") & C (\"-2\",\"-5\")\r
\n" ); document.write( "\n" ); document.write( "use distance formula:\r
\n" ); document.write( "\n" ); document.write( "the length of \"AB\" is\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "
Solved by pluggable solver: Distance Formula

\n" ); document.write( "
\n" ); document.write( " The first point is (x1,y1). The second point is (x2,y2)
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Since the first point is (-2, -3), we can say (x1, y1) = (-2, -3)
\n" ); document.write( " So \"x%5B1%5D+=+-2\", \"y%5B1%5D+=+-3\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Since the second point is (6, 1), we can also say (x2, y2) = (6, 1)
\n" ); document.write( " So \"x%5B2%5D+=+6\", \"y%5B2%5D+=+1\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Put this all together to get: \"x%5B1%5D+=+-2\", \"y%5B1%5D+=+-3\", \"x%5B2%5D+=+6\", and \"y%5B2%5D+=+1\"
\n" ); document.write( "
\n" ); document.write( " --------------------------------------------------------------------------------------------
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Now use the distance formula to find the distance between the two points (-2, -3) and (6, 1)
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"d+=+sqrt%28%28x%5B1%5D-x%5B2%5D%29%5E2+%2B+%28y%5B1%5D+-+y%5B2%5D%29%5E2%29\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"d+=+sqrt%28%28-2+-+6%29%5E2+%2B+%28-3+-+1%29%5E2%29\" Plug in \"x%5B1%5D+=+-2\", \"y%5B1%5D+=+-3\", \"x%5B2%5D+=+6\", and \"y%5B2%5D+=+1\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"d+=+sqrt%28%28-8%29%5E2+%2B+%28-4%29%5E2%29\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"d+=+sqrt%2864+%2B+16%29\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"d+=+sqrt%2880%29\"
\n" ); document.write( "
\n" ); document.write( "
\"d+=+sqrt%2816%2A5%29\"


\"d+=+sqrt%2816%29%2Asqrt%285%29\"


\"d+=+4%2Asqrt%285%29\"


\n" ); document.write( " \"d+=+8.94427190999916\"
\n" ); document.write( "
\n" ); document.write( " ==========================================================
\n" ); document.write( "
\n" ); document.write( " Answer:
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " The distance between the two points (-2, -3) and (6, 1) is exactly \"4%2Asqrt%285%29\" units
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " The approximate distance between the two points is about 8.94427190999916 units
\n" ); document.write( "
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\n" ); document.write( "
\n" ); document.write( " So again,
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Exact Distance: \"4%2Asqrt%285%29\" units
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Approximate Distance: \"8.94427190999916\" units
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "

\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "the length of \"AC\" is\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "
Solved by pluggable solver: Distance Formula

\n" ); document.write( "
\n" ); document.write( " The first point is (x1,y1). The second point is (x2,y2)
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Since the first point is (-2, -3), we can say (x1, y1) = (-2, -3)
\n" ); document.write( " So \"x%5B1%5D+=+-2\", \"y%5B1%5D+=+-3\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Since the second point is (-2, -5), we can also say (x2, y2) = (-2, -5)
\n" ); document.write( " So \"x%5B2%5D+=+-2\", \"y%5B2%5D+=+-5\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Put this all together to get: \"x%5B1%5D+=+-2\", \"y%5B1%5D+=+-3\", \"x%5B2%5D+=+-2\", and \"y%5B2%5D+=+-5\"
\n" ); document.write( "
\n" ); document.write( " --------------------------------------------------------------------------------------------
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Now use the distance formula to find the distance between the two points (-2, -3) and (-2, -5)
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"d+=+sqrt%28%28x%5B1%5D-x%5B2%5D%29%5E2+%2B+%28y%5B1%5D+-+y%5B2%5D%29%5E2%29\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"d+=+sqrt%28%28-2+-+%28-2%29%29%5E2+%2B+%28-3+-+%28-5%29%29%5E2%29\" Plug in \"x%5B1%5D+=+-2\", \"y%5B1%5D+=+-3\", \"x%5B2%5D+=+-2\", and \"y%5B2%5D+=+-5\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"d+=+sqrt%28%28-2+%2B+2%29%5E2+%2B+%28-3+%2B+5%29%5E2%29\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"d+=+sqrt%28%280%29%5E2+%2B+%282%29%5E2%29\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"d+=+sqrt%280+%2B+4%29\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"d+=+sqrt%284%29\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"d+=+2\"
\n" ); document.write( "
\n" ); document.write( " ==========================================================
\n" ); document.write( "
\n" ); document.write( " Answer:
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " The distance between the two points (-2, -3) and (-2, -5) is exactly 2 units
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\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "the length of \"BC\" is\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "
Solved by pluggable solver: Distance Formula

\n" ); document.write( "
\n" ); document.write( " The first point is (x1,y1). The second point is (x2,y2)
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Since the first point is (-2, -5), we can say (x1, y1) = (-2, -5)
\n" ); document.write( " So \"x%5B1%5D+=+-2\", \"y%5B1%5D+=+-5\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Since the second point is (6, 1), we can also say (x2, y2) = (6, 1)
\n" ); document.write( " So \"x%5B2%5D+=+6\", \"y%5B2%5D+=+1\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Put this all together to get: \"x%5B1%5D+=+-2\", \"y%5B1%5D+=+-5\", \"x%5B2%5D+=+6\", and \"y%5B2%5D+=+1\"
\n" ); document.write( "
\n" ); document.write( " --------------------------------------------------------------------------------------------
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Now use the distance formula to find the distance between the two points (-2, -5) and (6, 1)
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"d+=+sqrt%28%28x%5B1%5D-x%5B2%5D%29%5E2+%2B+%28y%5B1%5D+-+y%5B2%5D%29%5E2%29\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"d+=+sqrt%28%28-2+-+6%29%5E2+%2B+%28-5+-+1%29%5E2%29\" Plug in \"x%5B1%5D+=+-2\", \"y%5B1%5D+=+-5\", \"x%5B2%5D+=+6\", and \"y%5B2%5D+=+1\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"d+=+sqrt%28%28-8%29%5E2+%2B+%28-6%29%5E2%29\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"d+=+sqrt%2864+%2B+36%29\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"d+=+sqrt%28100%29\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"d+=+10\"
\n" ); document.write( "
\n" ); document.write( " ==========================================================
\n" ); document.write( "
\n" ); document.write( " Answer:
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " The distance between the two points (-2, -5) and (6, 1) is exactly 10 units
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\n" ); document.write( "\n" ); document.write( "so, \"AB=8.9\",\"AC=2\", and \"BC=10\"\r
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