document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1004846>Question 1004846</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need help on this question!<BR>\n" );
document.write( "here are two consecutive integers such that the sum of one-half of the smaller integer and five times the larger integer is equal to the product of 7 and 1 less than the smaller integer. Find the integers.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #621192 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=621192\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let x and x+1 be our consecutive integers, then<BR>\n" );
document.write( "(x/2) + 5(x+1) = 7(x-1)<BR>\n" );
document.write( "(x/2) + 5x +5 = 7x -7<BR>\n" );
document.write( "add 7 to both sides of =<BR>\n" );
document.write( "(x/2) +5x +12 = 7x<BR>\n" );
document.write( "multiply both sides of = by 2<BR>\n" );
document.write( "x +10x +24 = 14x<BR>\n" );
document.write( "11x +24 = 14x<BR>\n" );
document.write( "subtract 11x from both sides of =<BR>\n" );
document.write( "3x = 24<BR>\n" );
document.write( "x = 8<BR>\n" );
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document.write( "our two consecutive integers are 8 and 9<BR>\n" );
document.write( "check the answer<BR>\n" );
document.write( "(8/2) + 5(9) = 7(8-1)<BR>\n" );
document.write( "49 = 49<BR>\n" );
document.write( "our answer checks\r<BR>\n" );
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