document.write( "Question 1004842: Three times the least of three consecutive odd integers exceeds twice the greater by 17. Find the three integers. \n" ); document.write( "

Algebra.Com's Answer #621179 by vleith(2983) $\"\"$ $\"About$

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Let the smallest odd number be x. Then the next two odd numbers will be (x+2) and (x+4)\r
\n" ); document.write( "\n" ); document.write( "You are told
\n" ); document.write( " $\"3%2Ax+=+%282%2A%28x%2B4%29%29+%2B+17\"$
\n" ); document.write( " $\"3x+=+2x+%2B+8+%2B+17\"$
\n" ); document.write( " $\"3x+=+2x+%2B+25\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"x+=+25\"$ \r
\n" ); document.write( "\n" ); document.write( "So the numbers are 25, 27, and 29\r
\n" ); document.write( "\n" ); document.write( "Check you answer. Does 3*25 = 2* 29 + 17 ?? \n" ); document.write( "

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