document.write( "Question 1004829: a bank teller counted P100 and P50 bills. this totaled to 117 bills worth P9950. how many bills of each type did she have? \n" ); document.write( "

Algebra.Com's Answer #621176 by AnlytcPhil(1806) $\"\"$ $\"About$

You can put this solution on YOUR website!

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document.write( "The problem can also be done using only one\r\n" );
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document.write( "Let the number of P100s be x\r\n" );
document.write( "Then the number of P50s, using\r\n" );
document.write( "ONE PART = TOTAL MINUS OTHER PART,\r\n" );
document.write( "is 117-x.\r\n" );
document.write( "                      Value      Value\r\n" );
document.write( "Type       Number       of         of\r\n" );
document.write( " of          of        EACH       ALL\r\n" );
document.write( "bill        bills      bill      bills\r\n" );
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document.write( "P100s        x        P100     P100x\r\n" );
document.write( "P50s       117-x       P50     P50(117-x)\r\n" );
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document.write( "TOTALS      117      -----     P9950\r\n" );
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document.write( " The equation comes from the column on the right\r\n" );
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document.write( "           100x + 50(117-x) = 9950\r\n" );
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document.write( "           100x + 50(117-x) = 9950\r\n" );
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document.write( "          100x + 5850 - 50x = 9950\r\n" );
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document.write( "                 50x + 5850 = 9950\r\n" );
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document.write( "                        50x = 4100\r\n" );
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document.write( "                     x = 82 = the number of P100s.\r\n" );
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document.write( "The number of P50s is 117-x or 117-82 or 35 P50s.\r\n" );
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document.write( "Checking:  82 P100s is P8200 and 35 P50s is P1750\r\n" );
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document.write( "            That's 117 coins.\r\n" );
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document.write( "            And indeed P8200 + P1750 = P9950\r\n" );
document.write( "Edwin

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