document.write( "Question 1004805: Please help! I have already done most of the work.\r
\n" ); document.write( "\n" ); document.write( "Recently I asked about finding all real numbers in the interval [0, 2pi] that satisfy the equation.
\n" ); document.write( "I have worked through the problem but I feel like I have gotten stuck in some places. Here's the problem and where I'm at. Thank you in advance for your help!\r
\n" ); document.write( "\n" ); document.write( "\"+3+sec%5E2x+tanx+=+4+tanx+\"
\n" ); document.write( "= \"+tanx+%283+sec%5E2x+-+4%29+\"
\n" ); document.write( "= \"+tanx+=+0+\" and \"+3+sec%5E2x+-+4%29+=+0+\".\r
\n" ); document.write( "\n" ); document.write( "Starting first with \"+tanx+=+0+\".
\n" ); document.write( "= \"+x+=+tan%5E-1+%280%29+\"
\n" ); document.write( "= \"+x+=+0+\"
\n" ); document.write( "Now, I've seen other examples that use \"+tanx+=+0+\" and have the results be 0, as well as \"+%28pi%29+\" and \"+2%28pi%29+\" ...but I'm not quite sure why those last two should or shouldn't be included...why not \"+%28pi%29+%2F+2+\" or \"+3+%28pi%29+%2F+2+\" ? If you divide their sin by their cosine, doesn't it equal zero? So why choose \"+%28pi%29+\" and \"+2%28pi%29+\" with the zero and not others? Should I just leave it at 0, or should I include \"+%28pi%29+\" and \"+2%28pi%29+\" ?\r
\n" ); document.write( "\n" ); document.write( "Moving on to \"+3+sec%5E2x+-+4%29+=+0+\".
\n" ); document.write( "= \"+%283+sec%5E2x%29+=+4+\"
\n" ); document.write( "= \"+%28+sec%5E2+%28x%29%29+=+%284+%2F+3%29+\"
\n" ); document.write( "= \"+secx+=+sqrt%284+%2F+3%29+\"
\n" ); document.write( "= \"+secx+=+sqrt%2812%29+%2F+3+\"
\n" ); document.write( "= \"+x+=+sec%5E-1+%28sqrt%2812%29+%2F+3%29+\"
\n" ); document.write( "But now where do I go? Not quite sure how to find the arcsecant of something with a square root...How do I type that into my calculator? (I dont have a graphing calculator...but I can do sines, cosines and tangents with their inverses).\r
\n" ); document.write( "\n" ); document.write( "Help would be greatly appreciated. Thank you! :)
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Algebra.Com's Answer #621169 by ikleyn(52781)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "1.  Regarding first part of your question.\r\n" );
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document.write( "You got \r\n" );
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document.write( "tan(x) = 0. \r\n" );
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document.write( "The solutions of this equation are  x = 0, +/-\"pi\", +/-\"2pi\", +/-\"3pi\" , . . . , +/-\"k%2Api\", . . . .\r\n" );
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document.write( "Of them,  only 0, \"pi\" and \"2pi\"  belong to the segment  [\"0\", \"2pi\"]  that you pointed.\r\n" );
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document.write( "Other values that you are asking about,  like \"pi%2F2\", \"3pi%2F2\",  are not the roots of the equation  tan(x) = 0.\r\n" );
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document.write( "2.  Moving on to  \"3%2Asec%5E2%28x%29\" - \"4\" = \"0\".\r\n" );
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document.write( "It is  \"sec%28x%29\" = +/-\"2%2Fsqrt%283%29\",     or     \"1%2Fcos%28x%29\" = +/-\"2%2Fsqrt%283%29\"     or     cos(x) = +/-\"sqrt%283%29%2F2\".\r\n" );
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document.write( "If  cos(x) = \"sqrt%283%29%2F2\",  then x = \"pi%2F6\" and x = \"2pi+-+pi%2F6\" = \"11pi%2F6\" are the solutions in the segment  [\"0\", \"2pi\"].\r\n" );
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document.write( "If  cos(x) = -\"sqrt%283%29%2F2\",  then x = \"5pi%2F6\" and x = \"2pi+-+5pi%2F6\" = \"7pi%2F6\" are the solutions in the segment  [\"0\", \"2pi\"].\r\n" );
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document.write( "I recommend you to make a sketch of the unit circle, to mark the angles 0°, 30°, 45°, 60° and 90° in it and to write \r\n" );
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document.write( "the values of sin, cos and tan for these angles.\r\n" );
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document.write( "Then mark all other angles like 120°, 135°, 150°, 180° and so on till 360° and do the same.\r\n" );
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document.write( "After that you will be much more confident in such problems.\r\n" );
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