document.write( "Question 1004755: I have a quiz tomorrow and this is a problem on my homework, I could really use some help!\r
\n" ); document.write( "\n" ); document.write( "A chemist has a 60% acid solution and a 20% acid solution. How many millimeters of each should be used to make 140ml of a 35% acid solution? Let x represent the number of ml of the 60% acid solution. \r
\n" ); document.write( "\n" ); document.write( "Thanks so much!!
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Algebra.Com's Answer #621127 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
A chemist has a 60% acid solution and a 20% acid solution. How many millimeters of each should be used to make 140ml of a 35% acid solution? Let x represent the number of ml of the 60% acid solution.
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\n" ); document.write( "Using two equations::
\n" ); document.write( "Quantity:: s + t = 140 ml
\n" ); document.write( "Acid Eq:::0.60s + 0.20t = 0.35*140
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\n" ); document.write( "Modify for elimination:
\n" ); document.write( "60s + 60t = 60*140
\n" ); document.write( "60s + 20t = 35*140
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\n" ); document.write( "Subtract and solve for \"t\"::
\n" ); document.write( "40t = 25*140
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\n" ); document.write( "t = 87.5 ml (amt. of 20% solution needed
\n" ); document.write( "---
\n" ); document.write( "s = 140-t = 52.5 ml (amt. of 60% solution needed)
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\n" ); document.write( "OR
\n" ); document.write( "Using one equation:
\n" ); document.write( "acid + acid = acid
\n" ); document.write( "0.60x + 0.20(140-x) = 0.35*140
\n" ); document.write( "Multiply thru by 100 to get:
\n" ); document.write( "60x + 20*140 - 20x = 35*140
\n" ); document.write( "40x = 15*140
\n" ); document.write( "x = 52.5 ml (amt. of 60% solution needed)
\n" ); document.write( "140-x = 87.5 ml (amt. of 20% solution needed)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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