document.write( "Question 1004535: There are 648 more blue pens than red pens in stationary shop. After 1/6 of the blue pens and 3/4 of the red pens were sold, there were 1338 more blue pens than red pens left. How many pens were there at first. \n" ); document.write( "
Algebra.Com's Answer #621078 by maxitee(11)\"\" \"About 
You can put this solution on YOUR website!
Let's call the Blue pens B and the Red pens R.\r
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\n" ); document.write( "\n" ); document.write( "\"B+=+R+%2B+648\" (From the question)... Equation(i)\r
\n" ); document.write( "\n" ); document.write( "Upon selling 1/6 of blue pens, we now have a new amount of Blue pens. We shall call this new amount of blue pen Bn)\r
\n" ); document.write( "\n" ); document.write( "\"Bn+=+B-B%2F6\", (Where B is the original amount of Blues)\r
\n" ); document.write( "\n" ); document.write( "\"Rn=++R+-+3R%2F4\" (Same thing applies to Reds after selling 3/4)\r
\n" ); document.write( "\n" ); document.write( "\"Bn+=+Rn+%2B+1338\" (Because blues had 1338 more than red after sales)\r
\n" ); document.write( "\n" ); document.write( "\"B+-+B%2F6+=+R-+3R%2F4+%2B+1338\" (Substituting the values of Bn and Rn into above equation)\r
\n" ); document.write( "\n" ); document.write( "\"5B%2F6+=+R%2F4+%2B+1338\"\r
\n" ); document.write( "\n" ); document.write( "\"%285R+%2B+3240%29%2F6+=+%28R%2B5352%29%2F4\"\r
\n" ); document.write( "\n" ); document.write( "\"6R+%2B+32112+=+20R+%2B+12960\"
\n" ); document.write( "\"-14R+=+12960+-+32112\"\r
\n" ); document.write( "\n" ); document.write( "\"14R+=+19152\"\r
\n" ); document.write( "\n" ); document.write( "R= 1368 (Total amount of RED before sales)\r
\n" ); document.write( "\n" ); document.write( "B = 2016 (Total amount of Blues before sales)\r
\n" ); document.write( "\n" ); document.write( "How many pens? Simply add up B and R. I will allow you do that..
\n" ); document.write( "Enjoy!
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