document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1004672>Question 1004672</A>: <I><SPAN STYLE=\"word-break: break-all;\"> i dont know which topic this is but here is the equation \r<BR>\n" );
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document.write( "through: (-3, -2), prep. to y=5x -1 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #621076 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=621076\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The slope of the line perpendicular to the line y = 5x -1 is -1/5<BR>\n" );
document.write( "we now use the point given (-3, -2) and the slope -1/5 to construct the required line in standard form,<BR>\n" );
document.write( "-2 = (-1/5)*(-3) + b<BR>\n" );
document.write( "-2 = 3/5 + b<BR>\n" );
document.write( "b = -2 -3/5 = -13/5<BR>\n" );
document.write( "therefore the equation of the line is<BR>\n" );
document.write( "y = (-1/5)x - (13/5)<BR>\n" );
document.write( " </SPAN>\n" );
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