document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1004587>Question 1004587</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 100 liters of a 50% solution is obtained by mixing a 60% solution with a 20% solution. How many liters of each solution must be used to obtain the desired mixture?\r<BR>\n" );
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document.write( "Use linear equations please.. :) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #621034 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=621034\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call the amount of 60% solution you use, x.<BR>\n" );
document.write( "Then the amount of 20% solution is 100-x.<BR>\n" );
document.write( "The set up looks like this<BR>\n" );
document.write( ".60x + .20(100-x) = .50(100)<BR>\n" );
document.write( ".60x + 20 - .20x = 50<BR>\n" );
document.write( ".40x = 30<BR>\n" );
document.write( "x = 75 liters at 60% and then<BR>\n" );
document.write( "100-x = 25 liters at 20% </SPAN>\n" );
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