document.write( "Question 1004557: Bobby is 3 years older than Chris.Last year,the sum of their ages was 39.How old is each now \n" ); document.write( "
Algebra.Com's Answer #621017 by AnimalLover(6)![]() ![]() You can put this solution on YOUR website! So Bobby is 13 years old a year ago because 39/3=13 \n" ); document.write( "subtract three and you would get 10 \n" ); document.write( "so 10 is the age of Chris from last year \n" ); document.write( "if you add 1 to both ages, you will get their ages for this year \n" ); document.write( "13+1=14 \n" ); document.write( "so Bobby is 14 years old \n" ); document.write( "10+1=11 \n" ); document.write( "so Chris is 11 years old \n" ); document.write( "Bobby=14 \n" ); document.write( "Chris=11 \n" ); document.write( " |