document.write( "Question 1004443: A cargo plane left an airport at noon and flew toward New York at the average rate of 400 miles per hour. At 2 P.M. a passenger plane left the same airport for New York and flew the same route as the cargo plane at the average rate of 560 miles per hour. How many miles did the passenger plane fly before it overtook the cargo plane? \n" ); document.write( "
Algebra.Com's Answer #620947 by mananth(16946)\"\" \"About 
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when they meet the distance travveled by both is same\r
\n" ); document.write( "\n" ); document.write( "let that distance be x\r
\n" ); document.write( "\n" ); document.write( "cargo plane left at 12.00
\n" ); document.write( "speed = 400 mph
\n" ); document.write( "x/400 is the time taken by the cargo plane
\n" ); document.write( "x/t = 400
\n" ); document.write( "x=400t\r
\n" ); document.write( "\n" ); document.write( "Passenger jet left at 2.00
\n" ); document.write( "time time taken = t-2
\n" ); document.write( "speed = 560 mph\r
\n" ); document.write( "\n" ); document.write( "x/(t-2) = 560\r
\n" ); document.write( "\n" ); document.write( "x= 560(t-2)
\n" ); document.write( "400t=560(t-2)\r
\n" ); document.write( "\n" ); document.write( "400t = 560t-1120
\n" ); document.write( "160t = 1120
\n" ); document.write( "t = 7 hours\r
\n" ); document.write( "\n" ); document.write( "d=rt
\n" ); document.write( "d=400*7= 2800 miles\r
\n" ); document.write( "\n" ); document.write( "they flew 2800 miles \r
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