document.write( "Question 1004450: The sum of the areas of two squares is 89 square centimeters. The length of a side of the larger square is 3 centimeters more than the length of a side of the smaller square. Find the dimensions of each square. \n" ); document.write( "
Algebra.Com's Answer #620946 by mananth(16946)\"\" \"About 
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The sum of the areas of two squares is 89 square centimeters. The length of a side of the larger square is 3 centimeters more than the length of a side of the smaller square. Find the dimensions of each square. \r
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\n" ); document.write( "\n" ); document.write( "the length of a side of the smaller square. let it be x\r
\n" ); document.write( "\n" ); document.write( "Area = x^2\r
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\n" ); document.write( "\n" ); document.write( "The length of a side of the larger square is 3 centimeters more than .(x+3)
\n" ); document.write( "area = (x+3)^2\r
\n" ); document.write( "\n" ); document.write( "The sum of the areas of two squares is 89 square centimeters. \r
\n" ); document.write( "\n" ); document.write( "x^2+(x+3)^2=89\r
\n" ); document.write( "\n" ); document.write( "x^2+x^2+6x+9 = 89\r
\n" ); document.write( "\n" ); document.write( "2x^2+6x-80=0\r
\n" ); document.write( "\n" ); document.write( "/2
\n" ); document.write( "x^2+3x-40=0\r
\n" ); document.write( "\n" ); document.write( "x^2+8x-5x-40=0\r
\n" ); document.write( "\n" ); document.write( "x(x+8)-5(x+8)=0
\n" ); document.write( "(x+8)(x-5)=0
\n" ); document.write( "x=-8 OR x= 5
\n" ); document.write( "Ignore negative
\n" ); document.write( "dimensions of the squares are\r
\n" ); document.write( "\n" ); document.write( "5 by 5 cm and 8 by 8 cm
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