document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1004406>Question 1004406</A>: <I><SPAN STYLE=\"word-break: break-all;\"> An older person is 8 years older than 5 times the age of a younger person. The sum of their age is 26. Find their age. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #620939 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=620939\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call the older and younger, x and y.<BR>\n" );
document.write( "Then we have<BR>\n" );
document.write( "x = 5y + 8 and <BR>\n" );
document.write( "x + y = 26<BR>\n" );
document.write( "Substitute the first into the second and get<BR>\n" );
document.write( "5y + 8 + y = 26<BR>\n" );
document.write( "6y + 8 = 26<BR>\n" );
document.write( "6y = 18<BR>\n" );
document.write( "y = 3<BR>\n" );
document.write( "x is then 23. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );