document.write( "Question 1004424: Sanchez has a collection of pennies, nickels, and dimes worth $9.35. He has five more nickels than pennies and twice as many dimes as pennies. How many coins of each kind does he have?
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Algebra.Com's Answer #620933 by addingup(3677)\"\" \"About 
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.01p+.05n+.10d= 9.35
\n" ); document.write( "n= p+5
\n" ); document.write( "d= 2p
\n" ); document.write( "Let's rewrite the initial equation substituting the values of n and d:
\n" ); document.write( ".01p+.05(p+5)+.10(2p)= 9.35 Multiply on left to eliminate parentheses:
\n" ); document.write( ".01p+.05p+.25+.20p= 9.35 Add p on left and subtract .25 on both sides:
\n" ); document.write( ".26p= 9.10 Divide both sides by .26
\n" ); document.write( "p= 35 We have 35 pennies
\n" ); document.write( "5 more nickels than pennies: 35+5= 40 nickels
\n" ); document.write( "2 times more dimes than pennies: 35*2= 70 dimes
\n" ); document.write( "Proof
\n" ); document.write( "35*.01= .35
\n" ); document.write( "40*.05= 2.00
\n" ); document.write( "70*.10= 7.00
\n" ); document.write( "_ _ _ _------
\n" ); document.write( "Total....9.35 We have the correct answer
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