document.write( "Question 1004424: Sanchez has a collection of pennies, nickels, and dimes worth $9.35. He has five more nickels than pennies and twice as many dimes as pennies. How many coins of each kind does he have?
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Algebra.Com's Answer #620933 by addingup(3677)![]() ![]() You can put this solution on YOUR website! .01p+.05n+.10d= 9.35 \n" ); document.write( "n= p+5 \n" ); document.write( "d= 2p \n" ); document.write( "Let's rewrite the initial equation substituting the values of n and d: \n" ); document.write( ".01p+.05(p+5)+.10(2p)= 9.35 Multiply on left to eliminate parentheses: \n" ); document.write( ".01p+.05p+.25+.20p= 9.35 Add p on left and subtract .25 on both sides: \n" ); document.write( ".26p= 9.10 Divide both sides by .26 \n" ); document.write( "p= 35 We have 35 pennies \n" ); document.write( "5 more nickels than pennies: 35+5= 40 nickels \n" ); document.write( "2 times more dimes than pennies: 35*2= 70 dimes \n" ); document.write( "Proof \n" ); document.write( "35*.01= .35 \n" ); document.write( "40*.05= 2.00 \n" ); document.write( "70*.10= 7.00 \n" ); document.write( "_ _ _ _------ \n" ); document.write( "Total....9.35 We have the correct answer \n" ); document.write( " |