document.write( "Question 1004435: I forgot how to do this problem I am really struggling .. It says find the axis of symmetry, vertex, graph the function. And give the domain and range
\n" ); document.write( "F(x)=-x^2+10x-17
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Algebra.Com's Answer #620927 by Boreal(15235)\"\" \"About 
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-x^2+10x+17=f(x)
\n" ); document.write( "vertex x value is -b/2a, which is -(-10/2)=5
\n" ); document.write( "f(5)=-25+50-17=8
\n" ); document.write( "vertex is at (5,8)
\n" ); document.write( "Symmetrical around x=5
\n" ); document.write( "Next step is y-intercept when x=0 and that is at (0,-17)
\n" ); document.write( "Because of symmetry, the change in x from 5 to 0 causes y to change from 8 to -17
\n" ); document.write( "That means from -5 to -10, going the other way, the y-value is the same, -17.
\n" ); document.write( "There are now 3 points, the vertex, and (0,-17) and (-10,-17). One can put in 1,2 or other values for x, but these are enough to graph it.
\n" ); document.write( "Domain is all x values.
\n" ); document.write( "Range are all y values less than or equal to 8, which is at the vertex.
\n" ); document.write( "\"graph%28300%2C300%2C-10%2C15%2C-20%2C20%2C-x%5E2%2B10x-17%29\"
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