document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1004432>Question 1004432</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of the areas of two squares is 89 square centimeters. The length of a side of the larger square is 3 centimeters more than the length of a side of the smaller square. Find the dimensions of each square. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #620923 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=620923\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> smaller square has side x, area x^2<BR>\n" );
document.write( "larger has side (x+3), area x^2+6x+9<BR>\n" );
document.write( "the two add to 89 cm^2<BR>\n" );
document.write( "2x^2+6x+9=89<BR>\n" );
document.write( "2x^2+6x-80=-<BR>\n" );
document.write( "x^2+3x-40=0, factoring out a 2<BR>\n" );
document.write( "(x+8)(x-5)=0<BR>\n" );
document.write( "x=5, only sensible root<BR>\n" );
document.write( "small square is 5 x 5 cm or 25 cm^2<BR>\n" );
document.write( "larger square is 8 x 8 cm or 64 cm^2 </SPAN>\n" );
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