document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1004400>Question 1004400</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Roberto invested some money at 2.5% and then invested $3000 more than twice this amount at 3%. His total annual income from the two investments was $1325. Find the amount invested at 1.75% </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #620904 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=620904\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Roberto invested some money at 2.5% and then invested $3000 more than twice this amount at 3%. His total annual income from the two investments was $1325. Find the amount invested at 1.75% <BR>\n" );
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document.write( "Note: No money was invested at 1.75%<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "0.025x + 0.03(2x+3000) = 1325<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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document.write( " </SPAN>\n" );
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