document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1004393>Question 1004393</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A person wishes to mix coffee worth $12 per lb with coffee worth $6 per lb to get 90 lb of a mixture worth $8 per lb. How many pounds of the $12 and the $6 coffees will be needed? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #620901 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=620901\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x be the amount used of the $12 coffee.<BR>\n" );
document.write( "Then 90-x is the amount used of the $6 coffee.<BR>\n" );
document.write( "The set up looks like this<BR>\n" );
document.write( "12x + 6(90-x) = 8(90)<BR>\n" );
document.write( "which we finish as<BR>\n" );
document.write( "12x + 540 - 6x = 720<BR>\n" );
document.write( "6x + 540 = 720<BR>\n" );
document.write( "6x = 180<BR>\n" );
document.write( "x = 30 lbs of $12<BR>\n" );
document.write( "90-x = 60 lbs of $6<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );