document.write( "Question 1004388: Please help me solve this equation: \"x%5E2%2Bsqrt%28x%29=2\".
\n" ); document.write( "I know x=1 but I want to know the procedure.
\n" ); document.write( "

Algebra.Com's Answer #620891 by richard1234(7193)\"\" \"About 
You can put this solution on YOUR website!
Without any computation, x = 1 *has* to be the only real solution because the functions x^2 and sqrt(x) are strictly increasing when x >= 0 (note: if x < 0, then the LHS is non-real). Because x = 1 is a solution, it must be the only real solution.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Assuming complex-valued square roots, you can solve by isolating sqrt(x) and squaring:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "\r
\n" ); document.write( "\n" ); document.write( "And so on.
\n" ); document.write( "
\n" );