document.write( "Question 1004367: Find the point slope form of the equation of the line that is perpendicular to
\n" ); document.write( " 2x-3y=4 and also contains the point (-2,1).\r
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Algebra.Com's Answer #620883 by Cromlix(4381)\"\" \"About 
You can put this solution on YOUR website!
Hi there,
\n" ); document.write( "2x-3y=4
\n" ); document.write( "Put in y = mx + c form
\n" ); document.write( "-3y = -2x + 4
\n" ); document.write( "3y = 2x - 4
\n" ); document.write( "y = 2/3x - 4/3
\n" ); document.write( "Slope = 2/3
\n" ); document.write( "Lines that are perpendicular
\n" ); document.write( "to one another have slopes that
\n" ); document.write( "multiply together to give -1
\n" ); document.write( "m1 x m2 = -1
\n" ); document.write( "2/3 x m2 = -1
\n" ); document.write( "m2 = -3/2
\n" ); document.write( "Using line equation
\n" ); document.write( "y - b = m(x - a)
\n" ); document.write( "m = -3/2 and (a,b) = (-2,1)
\n" ); document.write( "y - 1 = -3/2(x -(-2))
\n" ); document.write( "y - 1 = -3/2x + 4
\n" ); document.write( "y - 1 = -3/2x + 4
\n" ); document.write( "y = -3/2x + 4 + 1
\n" ); document.write( "y = -3/2x + 5
\n" ); document.write( "Hope this helps :-)
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