document.write( "Question 1004367: Find the point slope form of the equation of the line that is perpendicular to
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document.write( " 2x-3y=4 and also contains the point (-2,1).\r
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Algebra.Com's Answer #620883 by Cromlix(4381)![]() ![]() You can put this solution on YOUR website! Hi there, \n" ); document.write( "2x-3y=4 \n" ); document.write( "Put in y = mx + c form \n" ); document.write( "-3y = -2x + 4 \n" ); document.write( "3y = 2x - 4 \n" ); document.write( "y = 2/3x - 4/3 \n" ); document.write( "Slope = 2/3 \n" ); document.write( "Lines that are perpendicular \n" ); document.write( "to one another have slopes that \n" ); document.write( "multiply together to give -1 \n" ); document.write( "m1 x m2 = -1 \n" ); document.write( "2/3 x m2 = -1 \n" ); document.write( "m2 = -3/2 \n" ); document.write( "Using line equation \n" ); document.write( "y - b = m(x - a) \n" ); document.write( "m = -3/2 and (a,b) = (-2,1) \n" ); document.write( "y - 1 = -3/2(x -(-2)) \n" ); document.write( "y - 1 = -3/2x + 4 \n" ); document.write( "y - 1 = -3/2x + 4 \n" ); document.write( "y = -3/2x + 4 + 1 \n" ); document.write( "y = -3/2x + 5 \n" ); document.write( "Hope this helps :-) \n" ); document.write( " |