document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1004367>Question 1004367</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the point slope form of the equation of the line that is perpendicular to<BR>\n" );
document.write( " 2x-3y=4 and also contains the point (-2,1).\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #620882 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=620882\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> -3y=-2x+4 rewriting the formula<BR>\n" );
document.write( "y=(2x/3)-(4/3)<BR>\n" );
document.write( "slope is 2/3<BR>\n" );
document.write( "perpendicular is negative reciprocal or -3/2 slope<BR>\n" );
document.write( "point slope formula is<BR>\n" );
document.write( "y-y1=m(x-x1)<BR>\n" );
document.write( "y-1=(-3/2)(x+2)= (-3x/2)-3<BR>\n" );
document.write( "y=(-3x/2)-2<BR>\n" );
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