document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1004345>Question 1004345</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What is the solution to y=x+15 y=2x please add shortcut steps. 8th grade student. Thanks! God bless! Need solution for x and y.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #620851 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=620851\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Okay, if two quantities are both equal to y, as in<BR>\n" );
document.write( "y=x+15 and<BR>\n" );
document.write( "y=2x<BR>\n" );
document.write( "then you can set them equal to each other...we can write<BR>\n" );
document.write( "x + 15 = 2x<BR>\n" );
document.write( "Now subtract x from both sides and get<BR>\n" );
document.write( "x = 15<BR>\n" );
document.write( "Then since y = 2x,<BR>\n" );
document.write( "y = 30 </SPAN>\n" );
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