document.write( "Question 1004328: log7(8x)=log7(2x)+log7(3x-5) \n" ); document.write( "

Algebra.Com's Answer #620832 by fractalier(6550) $\"\"$ $\"About$

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\n" ); document.write( "log7(8x)=log7(2x)+log7(3x-5)
\n" ); document.write( "log7(8x)=log7[(2x)(3x-5)]
\n" ); document.write( "Now exponentiate 7-to-the
\n" ); document.write( "8x = (2x)(3x-5)
\n" ); document.write( "8x = 6x^2 - 10x
\n" ); document.write( "6x^2 - 18x = 0
\n" ); document.write( "x^2 - 3x = 0
\n" ); document.write( "x(x-3) = 0
\n" ); document.write( "x = 0 or x = 3
\n" ); document.write( "You cannot take the log of zero, so x = 3. \n" ); document.write( "

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