document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1004190>Question 1004190</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The point P on the circle x^2+y^2=r^2 that is also on the terminal side of an angle ø in standard position given.Find the indicated trigometric function. (-4,-3) Find Cos Ø </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #620773 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=620773\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> cosine theta will be equal to -4/5.\r<BR>\n" );
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document.write( "the angle will be 180 - arccos(4/5) = 143.1301024 degrees.\r<BR>\n" );
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document.write( "the equivalent angle in the first quadrant is equal to 180 - 143.1301024 degrees which is equal to 36.86989765 degrees.\r<BR>\n" );
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document.write( "the triangle is a 3/4/5 triangle in the third quadrant.\r<BR>\n" );
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document.write( "it is in the third quadrant because the adjcent side on the x-axis is negative and the opposite side on the y-axis is also negative.\r<BR>\n" );
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document.write( "the hypotenuse is always positive.\r<BR>\n" );
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document.write( "the hypotenuse is 5 because 3^2 + 4^2 = 9 + 16 = 25 and sqrt(25) = 5.\r<BR>\n" );
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document.write( "this is based on pythagorus who says that a^2 + b^2 = c^2.\r<BR>\n" );
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document.write( "a diagram of your angle is shown below:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" src = \"http://theo.x10hosting.com/2015/111701.jpg\" alt=\"$$$\" </>\r<BR>\n" );
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document.write( "the radius of your circle is 5, and so the equation of the circle becomes x^2 + y^2 = 25.\r<BR>\n" );
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