document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1004245>Question 1004245</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a rectangle is 24 cms. If the length is increased by 4 and the width is decreased by 2, the area is decreased by 2 sq. cms. What are the dimensions of the original rectangle?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #620754 by </B><A HREF=/tutors/aboutme.mpl?userid=jkc52><B>jkc52(5)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jkc52><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=620754\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the length and width of the original rectangle be l and b cm.<BR>\n" );
document.write( "given that the perimeter of the rectangle is 24 cm<BR>\n" );
document.write( "therefore 2*(l+b)=24<BR>\n" );
document.write( "or l +b =12........................(1)<BR>\n" );
document.write( "the area of this rectangle a1=l*b<BR>\n" );
document.write( "as per the second condition (l+4)*(b-2)=a1-2<BR>\n" );
document.write( "therefore<BR>\n" );
document.write( "-2*l+4*b+l*b-8=a1-2<BR>\n" );
document.write( "or   l-2*b=-3.......................(2)\r<BR>\n" );
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document.write( "therefore solving 1 and 2 l=7 and b =5 cm </SPAN>\n" );
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