document.write( "Question 1004239: The Perimeters of two triangles is in the ratio of 2:4. The sum of their areas is 100 cm squared. Find the area of each triangle? \n" ); document.write( "
Algebra.Com's Answer #620753 by josgarithmetic(39618)![]() ![]() ![]() You can put this solution on YOUR website! That ratio is also 1:2. \n" ); document.write( "Let x,y,z be the lengths of each side for the small triangle. The altitude is also in the same ratio between the two triangles (because linear measures).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Small perimeter, x+y+z \n" ); document.write( "Large perimeter, 2(x+y+z) \n" ); document.write( "If h is the altitude of the small triangle, the 2h is altitude for large triangle.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Small area, \n" ); document.write( "large area, \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Their summed areas is \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "This can now be used for finding the value of each area.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Small Triangle, \n" ); document.write( "Large Triangle, \n" ); document.write( " \n" ); document.write( " |