document.write( "Question 1004218: I'm currently learning Bernoulli and Random Variables. I have tried this problem countless times and I can't seem to get it right. Anything can help! Thank you!\r
\n" ); document.write( "\n" ); document.write( "The probability that a randomly selected teenager watched a rented video at least once during a week was 0.74. What is the probability that at least 8 teenagers in a group of 10 watched a rented movie at least once last week? (Round your answer to four decimal places.)
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Algebra.Com's Answer #620751 by MathTherapy(10555)\"\" \"About 
You can put this solution on YOUR website!
I'm currently learning Bernoulli and Random Variables. I have tried this problem countless times and I can't seem to get it right. Anything can help! Thank you!\r
\n" ); document.write( "\n" ); document.write( "The probability that a randomly selected teenager watched a rented video at least once during a week was 0.74. What is the probability that at least 8 teenagers in a group of 10 watched a rented movie at least once last week? (Round your answer to four decimal places.)
\n" ); document.write( "P(X ≥ 8) =
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Binomial Probability Formula/Bernoulli Theorem: nCr pr q(n - r), where:
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document.write( "n = number of trials (10 in this case)
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document.write( "r = number of successes (8, 9, 10 in this case, since @ least 8 signifies such)
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document.write( "P = probability of success (.74 in this case)
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document.write( "q = probability of failure, or 1 - n (1 - .74, or .26, in this case)\r
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document.write( "Calculating 8 successes should result in a probability of:  0.274 
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document.write( "Calculating 9 successes should result in a probability of:  0.173
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document.write( "Calculating 10 successes should result in a probability of: 0.049\r
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document.write( "Calculating the probability that @ least 8 of 10 watched a rented movie = 0.274 + 0.173 + .049, or \"highlight_green%28.496%29\"\r
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document.write( "In MS Excel, you can do: 1 - BINOMDIST(7,10,.74,1). You should get the above probability\r
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document.write( "On a TI-83/84, you can enter: 1 - BINOMCDF(10,0.74,7). You should get the above probability \n" );
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