document.write( "Question 1004197: The sum of three numbers is
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\n" ); document.write( ". The third number is
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\n" ); document.write( " times the first. The first number is
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Algebra.Com's Answer #620728 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "let the first number be \"x\", the second number \"y\", and third number \"z\"
\n" ); document.write( "the sum of three numbers is \"129\"; so, we have \r
\n" ); document.write( "\n" ); document.write( "\"x%2By%2Bz=129\".....eq.1\r
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\n" ); document.write( "\n" ); document.write( "if the third number is \"4\" times the first, we have \"z=4x\"\r
\n" ); document.write( "\n" ); document.write( "if the first number is \"9\" more than the second, we have \"y=x-9\"\r
\n" ); document.write( "\n" ); document.write( "substitute it in eq.1\r
\n" ); document.write( "\n" ); document.write( "\"x%2B%28x-9%29%2B4x=129\".....eq.1\r
\n" ); document.write( "\n" ); document.write( "\"x%2Bx-9%2B4x=129\"\r
\n" ); document.write( "\n" ); document.write( "\"6x=129%2B9\"\r
\n" ); document.write( "\n" ); document.write( "\"6x=138\"\r
\n" ); document.write( "\n" ); document.write( "\"x=138%2F6\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28x=23%29\"\r
\n" ); document.write( "\n" ); document.write( "now find other two numbers\r
\n" ); document.write( "\n" ); document.write( "\"y=23-9\"=>\"highlight%28y=14%29\"\r
\n" ); document.write( "\n" ); document.write( "\"z=4%2A23\"=>\"highlight%28z=92%29\"\r
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