document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1004170>Question 1004170</A>: <I><SPAN STYLE=\"word-break: break-all;\"> during the first part of a kayak trip jack covered 60 km at certain speed he then travel 24 km at a speed that was for kilometers an hour slower if the total trip was eight hours what was the speed on each part of the trip </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #620723 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=620723\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> We will call the speed r (stands for rate, another word for speed)<BR>\n" );
document.write( "60/r+24/r-4= 8 The common denominator is r*r-4, let's bring the numbers together:<BR>\n" );
document.write( "(12(7r-20))/r(r-4)= 8 Multiply both sides by r(r-4):<BR>\n" );
document.write( "12(7r-20)= 8r^2-32r Multiply on left<BR>\n" );
document.write( "84r-240= 8r^2-32r Subtract right from left:<BR>\n" );
document.write( "-8r^2+116r-240=0 Factor:<BR>\n" );
document.write( "-4(r-12)(2r-5)=0 Divide by -4:<BR>\n" );
document.write( "(r-12)(2r-5)= 0 Break it into 2 equations:<BR>\n" );
document.write( "r= 12 or 2r= 5= r= 5/2 Let's try 12:<BR>\n" );
document.write( "60/12= 5<BR>\n" );
document.write( "24/(12-4)= 3<BR>\n" );
document.write( "5+3= 8 hours The correct answer is 12km/h during the first part and 8km/h after that<BR>\n" );
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