document.write( "Question 1004187: The perimeter of a rectangle is 68 cm.If the diagonal is 26cm,find the dimensions of the rectangle.What would the equation be for this? \n" ); document.write( "
Algebra.Com's Answer #620714 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
x and y dimensions, d diagonal.\r
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\n" ); document.write( "\n" ); document.write( "\"system%282x%2B2y=68%2Cx%5E2%2By%5E2=d%5E2%29\"\r
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\n" ); document.write( "\n" ); document.write( "Let d=26.\r
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\n" ); document.write( "\n" ); document.write( "\"system%28x%2By=34%2Cx%5E2%2By%5E2=26%5E2%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=34-x\"
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\n" ); document.write( "\"highlight_green%28x%5E2%2B%2834-x%29%5E2=26%5E2%29\"--------this can basically be the equation you want. You can simplify it and solve for x, and then use this to solve for y.\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%2B34%5E2-68x%2Bx%5E2-26%5E2=0\"
\n" ); document.write( "\"2x%5E2-68x%2B34%5E2-26%5E2=0\"
\n" ); document.write( "\"2x%5E2-68x%2B%2834%2B26%29%2834-26%29=0\"
\n" ); document.write( "\"2x%5E2-68x%2B%2860%29%288%29=0\"
\n" ); document.write( "\"2x%5E2-68x%2B480=0\"
\n" ); document.write( "\"highlight_green%28x%5E2-34x%2B240=0%29\"------now simplified, quadratic equation\r
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\n" ); document.write( "\n" ); document.write( "Discriminant, \"34%5E2-4%2A240=196=14%5E2\".\r
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\n" ); document.write( "\n" ); document.write( "\"x=%2834%2B-+14%29%2F2\", which would show BOTH dimensions x AND y.\r
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\n" ); document.write( "Dimensions would be 10 and 24.
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