document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1004187>Question 1004187</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a rectangle is 68 cm.If the diagonal is 26cm,find the dimensions of the rectangle.What would the equation be for this?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #620713 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=620713\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> L+W=34 (half the perimeter)<BR>\n" );
document.write( "L=34-W<BR>\n" );
document.write( "Pythagorean theorem<BR>\n" );
document.write( "W^2+(34-W)^2=26^2<BR>\n" );
document.write( "W^2+W^2-68W+1156=676; 2W^2-68W+480=0<BR>\n" );
document.write( "2(W^2-34W+240)=0,  factoring 2.<BR>\n" );
document.write( "(W-24)(W-10)=0<BR>\n" );
document.write( "W=24 or 10.  One is length, 24 cm, the other width, 10 cm.<BR>\n" );
document.write( "The perimeter is 68 cm.<BR>\n" );
document.write( "The square of 24 (576) and 10 (100)= square of diagonal, 26, cm, (676) </SPAN>\n" );
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