document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=12215>Question 12215</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 3/4B-1/2 =5/8B </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #6207 by </B><A HREF=/tutors/aboutme.mpl?userid=elima><B>elima(1433)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=elima><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=6207\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3/4B-1/2 =5/8B\r<BR>\n" );
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document.write( "First you need to get the b's together; so you will subtract 3/4b from both sides;\r<BR>\n" );
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document.write( "3/4b-3/4b-1/2=5/8b-3/4b<BR>\n" );
document.write( "So you are left with; -1/2=5/8b-3/4b; to add the fractions together you need to find the LCD; -1/2=5/8b-6/8b; -1/2=-1/8b\r<BR>\n" );
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document.write( "Now you want to multiply each side by the inverse of 1/8, which is 8/1;<BR>\n" );
document.write( "-1/2(8/1)=-1/8b(-8/1), that cancels out the 1/8 from the b, leaving b by itself.<BR>\n" );
document.write( "-1/2(-8/1)=b<BR>\n" );
document.write( "8/2=b; 4=b\r<BR>\n" );
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document.write( "Check:<BR>\n" );
document.write( "3/4(4)-1/2=5/8(4)<BR>\n" );
document.write( "12/4-1/2=20/8<BR>\n" );
document.write( "3-1/2=2 1/2<BR>\n" );
document.write( "2 1/2=2 1/2<BR>\n" );
document.write( "Got it! I hope you understand!=) </SPAN>\n" );
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