document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1004137>Question 1004137</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The second of two numbers is seven more than the first.  If the first in increased by 55, the result is five times the second.  Find the numbers.\r<BR>\n" );
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document.write( "I tried this, but it is not working out: y=(x+7)=(x+55=5y) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #620685 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=620685\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call the numbers x and y.<BR>\n" );
document.write( "From the facts in the problem<BR>\n" );
document.write( "y = x + 7<BR>\n" );
document.write( "and<BR>\n" );
document.write( "x + 55 = 5y<BR>\n" );
document.write( "Now substitute the first into the second and get<BR>\n" );
document.write( "x + 55 = 5(x + 7)<BR>\n" );
document.write( "x + 55 = 5x + 35<BR>\n" );
document.write( "Collect like terms and get<BR>\n" );
document.write( "20 = 4x<BR>\n" );
document.write( "x = 5 and then<BR>\n" );
document.write( "y = 12 </SPAN>\n" );
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