document.write( "Question 1004104: X is the midpoint of line ST. Line RX is perpendicular to line ST.
\n" ); document.write( "Prove: line RS is congruent to line RT.
\n" ); document.write( "Line RX is perpendicular to line ST: GIVEN
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\n" ); document.write( "X is the midpoint of line ST:GIVEN
\n" ); document.write( "SX is congruent to TX:?
\n" ); document.write( "?: SAS
\n" ); document.write( "Line RS is congruent to RT
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Algebra.Com's Answer #620678 by jim_thompson5910(35256)\"\" \"About 
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Drawing:
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NumberStatementReason
1.Line RX is perpendicular to line STGiven
2.Line RX is congruent to line RXReflexive Property of Congruence
3.X is the midpoint of line STGiven
4.Angle RXS = angle RXTAll perpendicular angles are congruent (and equal to 90 degrees)
5.SX is congruent to TXDefinition of Midpoint (uses line 3)
6.Triangle SRX is congruent to triangle TRXSAS Property of Congruence (uses lines 2,4,5)
7.Line RS is congruent to RTCPCTC
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\n" ); document.write( "\n" ); document.write( "Note:
\n" ); document.write( "CPCTC = Corresponding Parts of Congruent Triangles are Congruent
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